Assume that a drop of liquid evaporates by decreasing in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is ρ and L is its latent heat of vaporization.
A
ρ L/T
B
C
T/ ρ L
D
2T/ ρ L
Text Solution
Verified by ExpertsThe correct answer is:
D
When radius is decrease by dr
decrease in surface energy = Heat required for vaporization
Δ AT = Δ V ρ L
⇒ 4 × (2 π r)dr T = 4 π r 2 dr ρ L
⇒ r = 
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