At what temperature volume of an ideal gas at 0ºC becomes triple, for isobaric process?
Text Solution
Verified by ExpertsThe correct answer is:
A
We know that for ideal gas 
(at constant pressure
T 2 = 
× T 1 = 
× 273
= 3 × 273 K
T 2 = 819 K = 819 – 273
= 546ºC
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