A heat flux of 4000 J/s is to be passed through a copper rod of length 10 cm and area of cross-section 100 sq. cm. The thermal conductivity of copper is 400 W/mC. The two ends of this rod must be kept at a temperature difference of–
Text Solution
Verified by ExpertsThe correct answer is:
C
⇒ 4000
= 
⇒ Δ T = 100°C
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