A person sitting firmly over a rotating stool has his out stretched. If he folds his arms, his angular momentum about the axis of rotation
Text Solution
Verified by ExpertsThe correct answer is:
C
external torque 
= 0
Ι 1 ω 1 = Ι 2 ω 2
when he folds his arms Ι reduces
so Ι 1 > Ι 2
then ( ω 1 < ω 2 )
so, (L = constant)
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