A uniform thin ring of mass 0.4 kg rolls without slipping on a horizontal surface with a linear velocity of 10 cm/s. The kinetic energy of the ring is :
Text Solution
Verified by ExpertsThe correct answer is:
A
KE = 
mv 2 (1 + 1)
= mv 2
= 0.4 × 0.1 2
= 4 × 10 –3 .
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