A uniform rod of length λ is placed symmetrically on two walls as shown in figure. The rod is in equilibrium. If N 1 and N 2 are the normal forces exerted by the walls on the rod then
Text Solution
Verified by ExpertsThe correct answer is:
C
Balancing torque about the centre of the rod :
N 1 . 
– N 2 . 
= 0
⇒ N 1 = N 2 .
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