The total energy of electron in the ground state of hydrogen atom is –13.6 eV. The kinetic energy of an electron in the first excited state is:
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A
Total energy of electron in the orbit is equal to negative of its kinetic energy.
The energy of hydrogen atom when the electron revolves in nth orbit is
E = 
eV
In the ground stage; n = 1
E = 
= – 13.6 eV
For n = 2, E = 
= – 3.4 eV
So, kinetic energy of electron in the first excited state (i. e., for n = 2) is
K = – E – (–3.4) = 3.4eV
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