A parallel plate capacitor is filled by copper plate of thickness b. The new capacity will be-
Text Solution
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When a metal plate (conductor) of thickness b is inserted between the plates (without touching either), the electric field exists only in the gaps between the conductor and the plates - not inside the metal.
So, effectively, the space between the plates now has two dielectric gaps (air gaps) with total separation reduced by b.
The effective separation of the capacitor = 
Capacitance formula
For air-filled capacitor:
After inserting the conducting plate:
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