The amount of heat required to change 1 gm (0ºC) of ice into water of 100°C, is:
Text Solution
Verified by ExpertsThe correct answer is:
C
Heat required to convert 0ºC of ice into water = mL (L = Letent heat)
Now, heat required to rise the temperature of water from 0ºC to 100ºC.
= ms 
t
where s = specific heat, 
t = temperature rise
Total heat = mL + ms 
t
= 1 × 80 + 1 × 1 × (100 – 0)
= 180 cal
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