Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The arm PQ of a rectangular conductor is moving from x = 0 to x = 2b outwards and then inwards from x = 2b to x = 0 as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from x = 0 to x = b. Identify the graph showing the variation of different quantities with distance:

Text Solution
Verified by ExpertsThe correct answer is:
C
As rod moves in field area increases upto
n then field is absent and again flux is generated on return journey from x = b to x = 0. Thus plot A for flux.
curve B for emf
Power dissipated = vi
curve C for power dissipated
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A proton, a deuteron and an a-particle with same kinetic energy enter into a uniform magnetic field…
A proton and an alpha particle of the same enter in a uniform magnetic field which is acting perpen…
Two long parallel conductors S 1 and S 2 are separated by a distance 10 cm and carrying currents of…
Two parallel, long wires are kept 0.20 m apart in vacuum, each carrying current of x A in the same …
A charged particle moves along circular path in a uniform magnetic field in a cyclotron. The kineti…
Two long current carrying conductors are placed parallel to each other at a distance of 8 cm betwee…