A road CD of thermal resistance 10.0KW -1 is joined at the middle of an identical rod AB as shown in figure, The end A, B and D are maintained at 200 0 C, 100 0 C and 125 0 C respectively. The heat current in CD is P watt. The value of P is
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(2)
Sol.
Rods are identical so 
C is mid-point of AB, so 
at point C
2(200 − T) = T − 125 + 2(T − 100)
400 − 2 T = T − 125 + 2 T – 200
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