An electron and proton are separated by a large distance. The electron starts approaching the proton with energy 3eV. The proton captures the electrons and forms a hydrogen atom in second excited state. The resulting photon is incident on a photosensitive metal of threshold wavelength 
…. What is the maximum kinetic energy of the emitted photoelectron?
Text Solution
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Initially, energy of electron =+3eV finally, in 2 nd excited state, energy of electron 
=-1.51eV
Loss in energy is emitted as photon, So, photon energy 
Now, photoelectric effect equation 
= 1.41eV
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