Two small balls of the same size, having masses m 1 and m 2 (m 1 > m 2 ) are tied by a thin weightless thread and dropped from a certain height. Taking the force of buoyancy of air into account, the tension T in the thread during the flight, after the motion of the ball becomes uniform, will be
A
(m 1 – m 2 ) g
B
(m 1 - m 2 ) 
C
(m 1 + m 2 ) g
D
(m 1 + m 2 ) 
Text Solution
Verified by ExpertsThe correct answer is:
B
(m 1 -m 2 ) 
As both the ball are of same size, force of buoyancy on each is same. Therefore, in equilibrium
F + F = m 1 g + m 2 g or F = (m 1 +m 2 ) 
Considering the equilibrium of lower ball,
T + F = m 1 g
T=m 1 g-F
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