A block of mass m = 0 .1 kg is released from a height of 4 m on a curved smooth surface. On the horizontal surface, path AB is smooth and path BC is rough with a coefficient of friction 
= 0.1. If the impact of the block with the vertical wall at C is perfectly elastic, the total distance covered by the block on the horizontal surface before coming to rest will be (take g = 10 m s -2 )
Text Solution
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Total KE dissipated against friction = mgh = 4 J
Work done against friction in one trip across BC = mg 
x 2 = 0 .2 J
Total number of trips across BC = 
= 20
Total distance = 20 x BC + 19 x AB = 59 m
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