Three particles each of mass m = 1 kg, are located at the vertices of an equilateral triangle of side a = 4 m. The speed at which they must move to revolve in a circular orbit, under the influence of mutual gravitational force, circumscribing and preserving the equilateral triangle is 
, then the value of n is
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(0.50)
The net gravitational force on any particle due to the other two is
Now, 
For circular motion,
Solving it we obtain,
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