A drop of liquid of density p is floating half immersed in a liquid of density a and surface tension 7.5 x 10 -4 Ncm -1 . The radius of drop in cm will be: (Take: g = 10 m/s 2 )
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Buoyant force + surface tension = mg
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