The electric potential varies in space according to the relation: V = 3x + 4y. A particle of mass
10 Kg starts from rest from point (2, 3.2) under the influence of this field. Find the speed in m/s of the particle when it crosses the x-axis. The charge on the particle is +1C. Assume V and (x, y) are in S.I. units.
Text Solution
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(2)
Sol. Given, V = 3x + 4y
So, 
= – 
Or 
= – (3 
+ 4 
)
So, force on particle = q 
= – (3 
+ 4 
) × 1 N
and acceleration of particle = 
m/s 2
Now, a x = – 0.3 m/s 2 and a y = – 0.4 m/s 2
At x - axis y = 0
So, by (s = ut + 
at 2 ) in y direction:
– 3.2 = – 
× 
× t 2 ⇒ t = 4 sec.
Now, velocity at 4 sec. ⇒ v x = 
× 4 = – 1.2 m/sec
⇒ v y = 
× 4 = – 1.6 m/sec
So, velocity vector = – 1.2 
– 1.6 
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