Published by:
CGP EDU Academic Team
Published on: September 13, 2026
A capacitor of capacitance 150.0 
F is connected to an alternating source of emf given by E = 36 sin(120 
) V. The maximum value of current in the circuit is approximately equal to:
A
2 A
B
A
C
2 
A
A
D
A
Text Solution
Verified by ExpertsThe correct answer is:
A
The formula for maximum current is given by
I max = 
CV m ...(i)
The given data is
= 120 
V m = 36V
C = 150 
F
Substituting the values in equation (i)
= 2.036A 
2A
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For the given input voltage waveform , the output voltage waveform , across the capacitor is corr…
An AC circuit has and , connected in series. The quality factor for the circuit is
An elliptical loop having resistance , of semi major axis a, and semi minor axis is placed in a m…
A capacitor is discharging through a resistor R. Consider in time t 1 , the energy stored in the ca…
An alternating emf E = 440 sin100 t is applited to a circuit containing an inductance of H. If an…
A circuit element X when connected to an a.c. supply of peak voltage 100 V gives a peak current of …