In the network shown below, the charge accumulated in the capacitor in steady state will be:
Text Solution
Verified by ExpertsThe correct answer is:
D
In steady state, capacitor behaves as open circuit, so no current will flow.
The total resistance of the circuit is, R =(6 + 4) 
= 10 
The current flowing through the circuit is
Potential difference on 6 
resistor
V = 
x 6 = 1 8V
The charge on the capacitor is,
Q = CV' = 4 
F x 1.8 V = 7.2 
C
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A parallel plate capacitor with air between the plate has a capacitance of 15pF. The separation bet…
A capacitor has capacitance 5µF when it's parallel plates are separated by air medium of thickness …
A capacitor of capacitance 900µF is charged by a 100 V battery. The capacitor is disconnected from …
Two parallel plate capacitors C 1 and C 2 each having capacitance of 10µF are individually charged …
A charge particle of 2µC accelerated by a potential difference of 100V enters a region of uniform m…
A parallel plate capacitor with plate area A and plate separation d is filled with a dielectric mat…