In this figure the resistance of the coil of galvanometer G is 2 
. The emf of the cell is 4 V. The ratio of potential difference across C 1 and C 2 is
Text Solution
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Current flowing through both capacitors will be zero at steady state.
The potential difference across capacitor C 1 will be the sum of the potential difference across the resistor 6 
and the galvanometer resistance.
Mathematically,
V C1 = i[6 
+ R G ] ...
Similarly, the potential difference across capacitor C 2 will be the sum of the potential difference across the resistor 8 
and the galvanometer resistance. Mathematically,
Vc 2 = i[R G + 8 
] …
Divide equation by equation to obtain the required ratio.
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