Physics Motion in a Straight Line JEE Main 2023 - ( Motion in One Dimensional ) MCQ (Single Correct)

Form the v - t graph shown, the ratio of distance to displacement in 25 s of motion is:

A
1
B
C
D

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
C

The area under the velocity time graph gives the displacement. The area for t = 0 s to t = 25 s is

Area = 25 + 50 + 75 + 50 - 50 = 150 m

Hence, the displacement = 150 m

The distance is defined as the path taken by the object to travel from initial to final position. Also note that displacement is a vector quantity, but distance is a scalar quantity.

Distance

= (200 + 50) = 250 m

Therefore, required ratio

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.