As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be: (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
C
The velocities will be interchanged after collision.
Speed of P just before collision 
= 2m/s
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