A body of mass 200g is tied to a spring of spring constant 12.5 N/m, while the other end of spring is fixed at point O. If the body moves about O in a circular path on a smooth horizontal surface with constant angular speed 5 rad/s, then the ratio of extension in the spring to its natural length will be:
Text Solution
Verified by ExpertsThe correct answer is:
C
Natural length = L 0
Extension = x
Kx=m(L 0 +x) 
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