A Carnot engine with efficiency 50% takes heat from a source at 600 K. In order to increase the efficiency to 70%, keeping the temperature of sink same, the new temperature of the source will be:
Text Solution
Verified by ExpertsThe correct answer is:
B
Initially 
But 
Now efficiency is increased to 70% and T 2 = 300 K, Let temp of source T 1 = T
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