Home Physics System of Particles Rotational Motion JEE Main 2023 Two identical solid spheres each of mass 2 k…
Physics System of Particles Rotational Motion JEE Main 2023 MCQ (Single Correct)

Two identical solid spheres each of mass 2 kg and radii 10 cm are fixed at the ends of a light rod. The separation between the centres of the spheres is 40 cm. The moment of inertia of the system about an axis perpendicular to the rod passing through its middle point is______x 10 -3 kg m 2 .

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(176)

The moment of inertia of a sphere is given by the formula

Since there are two masses, the total moment of inertia about the axis perpendicular to the rod passing through the centre is

...(i)

The given data is

M = 2 kg

=(0.4-0.2)m = 0.2m

R = 0.1 m

Substituting the values in equation (i)

=(0. 016 + 0.16) kg m 2 = 0.176 kg m 2

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.