1 gram of ice is mixed with 1 gram of steam. At thermal equilibrium, the temperature of the mixture is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Here,
Mass of ice, 
Mass of steam, 
Latent heat of fusion of ice, 
Latent heat of steam, 
Specific heat of water, 
Heat required to convert ice at 
to water at 
is
Heat released by steam at 
to condense into water at 
is
As 
, whole of the steam will not condense, so the temperature of the mixture is 
.
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