In a YDSE experiment, thin films of thickness t 1 and t 2 are placed infront of slits S 1 and S 2 as shown in figure-1 and figure-2. It is observed that first minima and second maxima are produced at point 'O' in first and second experiment respectively. Point 'O' and 'S' are symmetrical with respect to S 1 and S 2 . Both the films have same refractive index if 
= 
, then calculate 'x'
Text Solution
Verified by ExpertsThe correct answer is:
D
(t 1 – t 2 ) (n – 1) = 
[(t 1 + t 2 )] (n – 1) = 2 λ
3t 1 = 5t 2 – 1
= 
⇒ 4t 1 – 4t 2 = t 1 t 2
= 3t 1 = 5t 2
= 
= 
x = 15.
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