Two slits separated by a distance of 1 mm, are illuminated with red light of wavelength 6.5 × 10 –7 m. The interference fringes are observed on a screen placed 1 m from the slits. Find the distance between the third dark fringe and the fifth bright fringe on the same side of the central maxima.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(1.625 mm)
Sol. As D >>d & λ << d.
Hence we can use β = 
so distance between 5 th bright fringe and 3 rd dark fringe = 5 β – (2 β + β /2)
= 
= 
= 1.625 mm
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