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CGP EDU Academic Team
Published on: September 12, 2026
Find the angular fringe width in a Young’s double slits experiment with blue-green light of wavelength 6000 Å. The separation between the slits is 3.0 × 10 –3 m.
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Understand the formula for angular fringe width in Young's double slit experiment. The angular fringe width (B8) can be calculated using the formula:
$$ heta = \frac{\lambda}{d}$$
where:
Step 2: Convert the wavelength into meters. Given: \(\lambda = 6000 \text{ Å} = 6000 \times 10^{-10} m = 6.0 \times 10^{-7} m\)
Step 3: Plug in the values into the formula. Here, \(d = 3.0 \times 10^{-3} m\)
$$\theta = \frac{6.0 \times 10^{-7}}{3.0 \times 10^{-3}}$$
Step 4: Calculate the angular fringe width:
$$\theta = 2.0 \times 10^{-4} ext{ radians}$$
Therefore, the angular fringe width is approximately:
$$\theta = 2.0 \times 10^{-4} ext{ radians}$$
$$ heta = \frac{\lambda}{d}$$
where:
- \(\theta\) = angular fringe width
- \(\lambda\) = wavelength of light
- \(d\) = separation between the slits
Step 2: Convert the wavelength into meters. Given: \(\lambda = 6000 \text{ Å} = 6000 \times 10^{-10} m = 6.0 \times 10^{-7} m\)
Step 3: Plug in the values into the formula. Here, \(d = 3.0 \times 10^{-3} m\)
$$\theta = \frac{6.0 \times 10^{-7}}{3.0 \times 10^{-3}}$$
Step 4: Calculate the angular fringe width:
$$\theta = 2.0 \times 10^{-4} ext{ radians}$$
Therefore, the angular fringe width is approximately:
$$\theta = 2.0 \times 10^{-4} ext{ radians}$$
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