A source emitting two light waves of wavelengths 580 nm and 700 nm is used in a young's double slit interference experiment. The separation between the slits is 0.20 mm and the interference is observed on a screen placed at 150 cm from the slits. Find the linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
0.9 mm
Sol. As λ << d
⇒ β 1 = 
β 2 = 
So , β 2 – β 1 = 
= 
= 0.9 mm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
What is the effect on the fringe width of interference fringes in a Young's double slit experiment …
Two slits separated by a distance of 1 mm, are illuminated with red light of wavelength 6.5 × 10 –7…
In a Young’s double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus…
Find the angular fringe width in a Young’s double slits experiment with blue-green light of wavelen…
A flint glass and a crown glass are fitted on the two slits of a double slit apparatus. The thickne…
Find the thickness of a plate which will produce a change in optical path equal to one fourth of th…