If the first minima in a Young’s slit experiment occurs directly infornt of one of the slits. (distance between slit & screen D = 12 cm and distance between slits d = 5 cm) then the wavelength of the radiation used is :
A
2 cm only
B
4 cm only
C
2m, 
cm, 
cm
cm, cm
D
4cm, 
cm, 
cm
cm, cm
Text Solution
Verified by ExpertsThe correct answer is:
A
Notice that d is not very small than D; so we can not use Δ p = d sin θ .
S 1 P – S 2 P = Δ P = 
{ first minima}
⇒ 
– (12) = 
get λ = 2 cm
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