Home Physics Wave Optics General In an interfrence arrangement similar to You…
Physics Wave Optics General MCQ (Single Correct)

In an interfrence arrangement similar to Young's double- slit experiment, the slits S 1 & S 2 are illuminated with coherent microwave sources, each of frequency 10 6 Hz. The sources are synchronized to have zero phase difference. The slits are separated by a distance d = 150.0 m and screen is at very large distance from slits. The intensity I( θ ) is measured as a function of θ , where θ is defined as shown. Screen is at a large distance. If I 0 is the maximum intensity then I ( θ ) for 0 ≤ θ ≤ 90º is given by:

A
I ( θ ) = for θ = 30º
B
I ( θ ) = for θ = 90º
C
I ( θ ) = I 0 for θ = 0º
D
I ( θ ) is constant for all values of θ .

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The correct answer is:
CHECK THE SOLUTION.

( a,c)

Sol. for θ = 30º; Δ P = d sin 30º = (150 m) × = 75 m.

⇒ Δφ = 75 × = =

⇒ I res = I + I + 2 I cos ( Δφ ) = 2I

where I = {  maximum intensity = I 0 = 4 I } ⇒ I res =

θ = 0º will automatically correspond to central maxima.

θ = 90º will correspond to path diff = d. = 150 m ⇒ Δφ = = π

⇒ minima

Hence intensity will be 0 at θ = 90º.

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