Home Physics Wave Optics JEE (Advanced) / IIT - JEE Problems ( Previous Years ) In a Young's double slit experiment, the sep…
Physics Wave Optics JEE (Advanced) / IIT - JEE Problems ( Previous Years ) MCQ (Single Correct)

In a Young's double slit experiment, the separation between the two slits is d and the wavelength of the light is λ . The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2. Choose the correct choice(s).

A
If d = λ , the screen will contain only one maximum
B
If λ < d < 2 λ , at least one more maximum (besides the central maximum) will be observed on the screen
C
If the intensity of light falling on slit 1 is reduced so that it becomes equal to that of slit 2, the intensities of the observed dark and bright fringes will increase
D
If the intensity of light falling on slit 2 is increased so that it becomes equal to that of slit 1, the intensities of the observed dark and bright fringes will increase

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The correct answer is:
CHECK THE SOLUTION.

(a,b)

If d = λ , then maximum path difference will be less than λ . So there will be only central maximum on the screen.

If λ < d < 2 λ , then the maximum path difference will be less than 2 λ .

So there will be two more maximum on screen

corresponding to path difference Δ x = λ

So and are correct.

Intensity of dark fringe becomes zero when intensities of two slits are equal. Initial intensity at both the slits are unequal so there will some brightness at dark fringe. Hence when intensity of both slits is made same the intensity at dark on screen shall decrease to zero. So both and are false.

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