Physics Transmission of Heat JEE (Advanced) / IIT-JEE Problems (Previous Years) MCQ (Single Correct)

A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat ‘Q’ flows only from left to right through the blocks. Then in steady state

A
heat flow through A and E slabs are same
B
heat flow through slab E is maximum
C
temperature difference across slab E is smallest
D
heat flow through C = heat flow through B + heat flow through D.

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The correct answer is:
CHECK THE SOLUTION.

(a, c, d)

: At steady state, heat flow through A and E are same.

: T = i × R

‘i’ is same for A and E but R is smallest for E.

: i B =

i C =

i D =

if i c = i B + i D

Hence

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