The work done in blowing a bubble of volume V is W, then what is the work done in blowing a soap bubble of volume 2V?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(2 2/3 W)
Sol. Given W = 2 × (4 π R 2 ) × T
where 
= V .........(i)
and we want of find W’ = 2 × (4 π ) (R’) 2 × T
where 
(R’) 3 = 2V. ........(ii)
Dividing equs. (i) and (ii)
= 
⇒ R ’ = 
R.
So, W’ = 2T × 4 π × 
. R 2 = 
(4 π 2TR 2 ) = 
W.
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