There is a soap bubble of radius 2.4 × 10 -4 m in air cylinder which is originally at the pressure 10 5 N/m 2 . The air in the cylinder is now compressed isothermally until the radius of the bubble is halved. Calculate now the pressure (in atm) of air in the cylinder. The surface tension of the soap solution is 0.08 N/m
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(8)
Sol. Similar to question no. 37,
p 2 = 8p 1 + 
= 8 × 10 5 + 
= 8.08 × 10 5 N/m 2
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The temperature at which the surface tension of water is zero
Water rises to a height h in a capillary tube lowered vertically into water to a depth λ as shown i…
A soap bubble of radius r 1 is placed on another soap bubble of radius r 2 (r 1 < r 2 ). The radius…
At critical temperature, the surface tension of a liquid:
The excess pressure inside a soap bubble is equal to 2 mm of kerosene (density 0.8 g cm –3 ). If th…
Match the column
Column - IColumn - II(a) Spliting of brigger drop into small drops(P) Temperaturec…