A drop of liquid of radius R = 10 –2 m having surface tension 
divides itself into K identical drops. In this process the total change in the surface energy Δ U = 10 –3 J. If K = 10 α then the value of α is:
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(6)
Sol. R = K 1/3 r
Δ U = S.K.4 π r 2 – S.4 π R 2
Δ U = 4 π S 
= 0.1 × 10 –4 [K 1/3 – 1] = 10 –3
K 1/3 – 1 = 10 2
K 1/3 = 101 = (10 α ) 1/3
α = 6
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A glass tube of uniform internal radius (r) has a valve separating the two identical ends. Initiall…
Two soap bubbles A and B are kept in a closed chamber where the air is maintained at pressure 8 N/m…
When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. A…
Four point charges, each of +q, are rigidly fixed at the four corners of a square planar soap film …
A glass capillary tube is of the shape of a truncated cone with an apex angle α so that its two end…
A uniform capillary tube of inner radius r is dipped vertically into a beaker filled with water. Th…