A tube of diameter d and of length λ unit is open at both the ends. Its fundamental frequency of resonance is found to be v 1 . The velocity of sound in air is 330 m/sec. One end of tube is now closed. The lowest frequency of resonance of tube is now v 2 . Taking into consideration the end correction, 
is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
= λ + .6d, v 1 = 
= λ + .3d, v 2 = 
= 
= 
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