To resonate a 1m tube closed at one end, if we use different tuning forks, we get different results. Match the following according to result of using tuning fork of certain frequency. (Velocity of sound = 320 m/s)
Tuning fork | Result |
(a) 240 Hz | (p) Moderate sound will be generated |
(b) 320 Hz | (q) Violent sound will be generated |
(c) 400 Hz | (r) Only third harmonic will be activated |
(d) 500 Hz | (s) Only fifth harmonic will be activated |
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
q, r, p, q, s, p
Sol. From standing wave equation
v = (400) (0.8) = 320 m/sec and natural freq. can be 
, 
, 
..........
80, 240, 400, 560 Hz................
(i) For f = 240, resonance will occur, so only third harmonic will be activated and air column will vibrate violently with purely third harmonic f = 240 Hz.
(ii) For f = 400 Hz, also resonance will occur and air column will vibrate purely with fifth harmonic.
(iii) For f = 320, f = 500 Hz, forcing freq. is not matching with any of the natural freq. So resonance will not occur and air column will vibrate moderately, and there will be some contributions of all harmonics.
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