In the figure shown an observer O 1 floats (static) on water surface with ears in air while another observer O 2 is moving upwards with constant velocity V 1 = V/5 in water. The source moves down with constant velocity V s = V/5 and emits sound of frequency 'f'. The velocity of sound in air is V and that in water is 4V. For the situation shown in figure:

Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
(a, c, d)
For observer O 1 , λ 1 =
= 
For O 2 , there is change of medium hence at the surface of water, keeping frequency unchanged

⇒ λ w = 4λ a = 

f'' =
=
=
= 
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