A source of sonic oscillations with frequency f = 1700 Hz and a receiver are located at the same point. At the moment t = 0 the source starts receding from the receiver with constant acceleration a = 10.0 m/s 2 . Find the oscillation frequency registered by the stationary receiver at t = 10.0 second after the start of the motion, assuming the velocity of the sound to be equal to v = 340m/s. [You can find the answer in variables]
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(1.35 Khz)
First detector and source (s)
are at O. Now source
start receding with acceleration a and in time t 1 it reaches at B and sound emitted at that moment reaches to the detector in time t 2 here in question t 1 + t 2 = t = 10 second.
At B velocity of source V S = at 1
if we consider two consecutive sound wave reaching to D starting from B
first wave will take t 2 = 
next wave t 11 = T + 
= 
time period = t 11 – t 2 = 
frequency = 
= 
f 1 = 
.......(1)
Now X = Vt 2 = V (t – t 1 )
X = 
a (t – t 2 ) 2 = 
at 1 2 
at 1
2 = Vt – Vt 1 at 1 2 + 2Vt 1 – 2Vt = 0
t 1 = 
t 1 is positive so
t 1 = 
Put this value of t 1 in equation (1)
f 1 = 
= 1.35 khz.
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