A satellite revolving around the earth at a certain height experiences acceleration due to
gravity equal to
, where
is the acceleration due to gravity on the earth's surface. If R is the radius of earth, then the square of time period of the satellite's revolution is equal to
. The value of K is
Text Solution
Verified by ExpertsThe correct answer is:
B
Acceleration due to gravity at height h from the surface of earth 
with height, 

Distance of satellite from center (
)

Time period of revolution is given by


Comparing given relation with above relation, above relation find

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