A particle is projected with a velocity
, 2m away from a vertical wall. After striking the wall it lands at …………… away from the wall. B
Text Solution
Verified by ExpertsThe correct answer is:
D
T = 
t = 3/6 = 0.5 s
x = u x (T - t) = 6(1.6 – 0.5) = 6.6 m

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A projectile fired with initial velocity u at some angle θ has a range R. If the initial velocity b…
The range of a projectile for a given initial velocity is maximum when the angle of projection is …
The angle of projection at which the horizontal range and maximum height of projectile are equal is
A ball is thrown upwards and it returns to ground describing a parabolic path. Which of the followi…
At the top of the trajectory of a projectile, the directions of its velocity and acceleration are
The height y and the distance x along the horizontal plane of a projectile on a certain planet (wit…