A bomb of mass 9 kg explodes into two parts. One part of mass 3 kg moves with velocity 16 m/s, the kinetic energy of the other part is:
Text Solution
Verified by ExpertsThe correct answer is:
A
From momentum conservation principle
0 = 3(16) + 6 
⇒ 
= (–8) m/s
and K 2 = 1/2 m 2 v 2 2 = 1/2 ⋅ 6 ⋅ (–8) 2 = 192 J
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