A stone of mass 500 g is dropped from the top of a tower of 100 m height simultaneously other stone of mass 1 kg is thrown horizontally with a speed of 10 m/s from same point. The height of centre of mass of the above two stone system after 3 sec is: (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
C
If height of stones is h 1 and h 2 after t = 3 sec then,
h 1 = 100 – 
gt 2 = 55 m
h 2 = 100 – 
gt 2 = 55 m
h CM = 
= 55 m
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