A portion of a ring of radius 
has been removed as shown in figure. Mass of the remaining portion is 
. Centre of the ring is at origin 
. Let 
and 
be the moments of inertia passing through points 
and 
are perpendicular to the plane of the ring. Then,
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
Whole mass has equal distance from the center 
.
Hence, 
. Further, center of mass of the remaining portion will be to the left of point 
. More the distance of axis from centre of mass, more is the moment of inertia. Hence, 
.
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