From a circular ring of mass 
and radius 
, an arc corresponding to a 
sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is 
times 
. Then, the value of 
is [NEET 2021]
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
An arc corresponding to a 
sector in the circular ring is removed, means one-fourth part of
circular ring is removed. Then, the mass of the removed circular ring,
Now the moment of inertia of the remaining part,
Comparing with 
The value of 
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A solid sphere is in rolling motion. In rolling motion a body possesses translational kinetic energ…
A solid sphere is rotating freely about its symmetry axis in free space. The radius of the sphere i…
Three objects, : (a solid sphere), : (a thin circular disk) and : (a circular ring), each have t…
The moment of the force, at , about the point , is given by
A rope is wound around a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceler…
Two discs of same moment of inertia rotating about their regular axis passing through centre and pe…