A bullet of mass 10 g moving horizontally with a velocity of 
strikes a wooden block of mass 2 kg which is suspended by light inextensible string of length 5 m.
As a result, the center of gravity of the block is found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be
Text Solution
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Given, mass of bullet,
Velocity, 
Mass of wooden block, 
Length of string, 
Let the velocity of bullet and the block after collision be 
and 
.
Block rises, 
PE at the maximum height 
at bottom of the block
Let 
be the initial velocity of the bullet, then according to the conservation of momentum,
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