The Young's modulus of steel is twice that of brass. Two wires of the same length and of the same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights added to the steel and brass wires must be in the ratio of
Text Solution
Verified by ExpertsThe correct answer is:
C
Young modulus 
and
are the same for both the wires.

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Stress-strain curve for four metals are shown in figure. The maximum Young's modulus of elasticity …
Two stress-strain graphs A and B are drawn by a student (as shown below) but he forgets to specify …
In plotting stress versus strain curves for two materials P and Q, a student by mistake puts strain…
Diagram shows the stress-strain graph for a metal wire. In the graph, the region in which Hooke's l…
The graph shows the behaviour of a length of wire in the region for which the substance obeys Hooke…
Two wires of copper having the length in the ratio and their radii ratio as are stretched by the …