A gas undergoes a change of state during which 100 J of heat is supplied to it and it does 20 J of work. The system is brought back to its original state through a process during which 20 J of heat is released by the gas. The work done by the gas in the second process is -
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A
In first process
Q = W + Δ U
100 = 20 + Δ U
Δ U = 80 J
In return process
– 20 = W – 80 ⇒ W = 60 J
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